WebAug 22, 2012 · isin() is ideal if you have a list of exact matches, but if you have a list of partial matches or substrings to look for, you can filter using the str.contains method and regular expressions. For example, if we want to return a DataFrame where all of the stock IDs which begin with '600' and then are followed by any three digits: >>> … WebJust for completeness, one could also try data [data ["Var1"] > 10, , drop = FALSE]. drop works when the result is just one line/column and R tries to simplify it. – Roman Luštrik Nov 29, 2012 at 9:12 Add a comment 10 Another method utilizing the dplyr package: library (dplyr) df <- mtcars %>% filter (mpg > 25) Without the chain (%>%) operator:
filtering data frame based on NA on multiple columns
WebSep 27, 2024 · Assuming that index is called df1, and your second dataframe that you want to filter is df2, I would do this using dplyr: library (dplyr) df.result <- left_join (df2, df1, by = "id") %>% filter (date.x > date.y) %>% select (-date.y) eta: this would be the result: id date.x 1 id1 2016-06-24 2 id3 2016-06-27 Share Improve this answer Follow WebR Filter DataFrame by Column Value NNK R Programming July 1, 2024 How to filter the data frame (DataFrame) by column value in R? We will use the … green firs shopping center
How to filter R dataframe by multiple conditions?
WebSet newDF equal to the subset of all rows of the data frame <-df [, (rows live in space before the comma and after the bracket) where the column names in df which ( (names (df) when compared against the matching names that list … WebAnother option could be using the function filter from dplyr. Here is a reproducible example: foo = data.frame (location = c ("here", "there", "here", "there", "where"), x = 1:5, y = 6:10) library (dplyr) filter (foo, location == "there") #> location x y #> 1 there 2 7 #> 2 there 4 9 Created on 2024-09-11 with reprex v2.0.2 Share Follow WebNov 29, 2014 · library (dplyr) df <- data.frame (this = c (1, 2, 2), that = c (1, 1, 2)) column <- "this" df %>% filter (!!as.symbol (column) == 1) # this that # 1 1 1 Using alternative solutions Other ways to refer to the value "this" of the variable column inside dplyr::filter () that don't rely on rlang's injection paradigm include: flushed away big cheese